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The MCQs below are drawn from the Mathematics subject category.
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7361
In a 40 L mixture of milk and water, 10% is water. How much water must be added to make water 20% of the new mixture?
A. 4 L
B. 5 L
C. 6 L
D. 8 L
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Explanation
Initial water = 4 L, Milk = 36 L. Let added water be x. New total = 40+x. New water = 4+x. We want (4+x)/(40+x) = 0.20. Solving gives 4 + x = 8 + 0.2x. 0.8x = 4. x = 5 L.
7362
In a zoo, 30% are monkeys, 40% are deer, and the remaining are bears. If there are 150 bears, total animals?
A. 300
B. 400
C. 500
D. 600
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Explanation
Bears percentage = 100% - (30% + 40%) = 30%. 30% of total = 150. Total = 150 / 0.30 = 500.
7363
Population of a town is 8000. If males increase by 6% and females by 10%, the population becomes 8600. Number of females?
A. 2000
B. 3000
C. 3500
D. 3800
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Explanation
M + F = 8000. New: 1.06M + 1.10F = 8600. Substitute M = 8000 - F: 1.06(8000 - F) + 1.10F = 8600 -> 848 + 0.04F = 8600 -> 0.04F = 152 -> F = 3800.
7364
The population of a town was 160000. In 3 years it increased to 185220. The annual rate of increase is?
A. 4%
B. 5%
C. 6%
D. 7%
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Explanation
P = P0(1 + r/100)^3. 185220 = 160000(1 + r/100)^3. (1 + r/100)^3 = 185220 / 160000 = 9261 / 8000 = (21/20)^3. So 1 + r/100 = 1.05. r = 5%.
7365
A tree's height increases by 10% annually. If its present height is 121 cm, what was its height 2 years ago?
A. 90 cm
B. 100 cm
C. 110 cm
D. 120 cm
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Explanation
Let original height be h. h * (1.10)^2 = 121. h * 1.21 = 121. h = 100 cm.
7366
The population of a town increases from 60,000 to 65,000. What is the percentage increase?
A. 8.33%
B. 8.5%
C. 9.1%
D. 10%
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Explanation
Increase = 5000. Percentage increase = (Increase / Original) * 100 = (5000 / 60000) * 100 = 8.33%.
7367
Value of property depreciates 10% per year. Present value is 810,000. What was its value 2 years ago?
A. 900000
B. 1000000
C. 1100000
D. 1200000
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Explanation
Let old value be x. x * (0.9)^2 = 810,000. x * 0.81 = 810,000. x = 1,000,000.
7368
Value of a car depreciates by 20% every year. If current value is 400,000, what will be its value after 2 years?
A. 240000
B. 250000
C. 256000
D. 300000
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Explanation
Value = 400,000 * (1 - 0.20)^2 = 400,000 * (0.8)^2 = 400,000 * 0.64 = 256,000.
7369
A town's population is 50,000. It increases by 10% every year. What will be the population after 1 year?
A. 55000
B. 56000
C. 60000
D. 60500
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Explanation
Increase = 10% of 50000 = 5000. New population = 50000 + 5000 = 55000.
7370
The population of a village is 8000. It decreases by 5% annually. What will it be after 2 years?
A. 7200
B. 7220
C. 7250
D. 7500
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Explanation
P = 8000 * (1 - 0.05)^2 = 8000 * 0.95^2 = 8000 * 0.9025 = 7220.
