Verified past-paper data not yet uploaded
No verified paper has been uploaded for AJKPSC-PMS Mathematics Set-10 yet. The MCQs below are drawn from the Mathematics subject category.
Divide the numbers inside a single root: sqrt(24 / 6) = sqrt(4). The square root of 4 simplifies to the whole number 2.
Using the quotient rule for surds, sqrt(a) / sqrt(b) = sqrt(a/b). So, sqrt(15) / sqrt(3) = sqrt(15 / 3) = sqrt(5).
Multiply the contents of the square roots: sqrt(8 * 2) = sqrt(16). The square root of 16 is precisely 4.
Multiply the numbers inside the roots: sqrt(12 * 3) = sqrt(36). The square root of 36 is an integer, 6.
Multiply the outside coefficients together and the inside numbers together. (2 * 3) * sqrt(3 * 2) gives 6 * sqrt(6), which is 6 sqrt(6).
Multiplying a square root by itself results in the number inside the root. sqrt(5) * sqrt(5) = sqrt(25), and the square root of 25 is 5.
According to the product rule for surds, sqrt(a) * sqrt(b) = sqrt(ab). So, sqrt(2) * sqrt(3) = sqrt(2 * 3) = sqrt(6).
Simplify each surd. sqrt(98) = sqrt(49 * 2) = 7 sqrt(2). sqrt(72) = sqrt(36 * 2) = 6 sqrt(2). Subtracting gives 7 sqrt(2) - 6 sqrt(2) = sqrt(2).
Simplify each term: sqrt(32) = 4 sqrt(2), sqrt(8) = 2 sqrt(2), sqrt(50) = 5 sqrt(2). Substitute and evaluate: 4 sqrt(2) + 2 sqrt(2) - 5 sqrt(2) = 6 sqrt(2) - 5 sqrt(2) = sqrt(2).
Simplify both terms. sqrt(75) = sqrt(25 * 3) = 5 sqrt(3). sqrt(48) = sqrt(16 * 3) = 4 sqrt(3). Subtracting gives 5 sqrt(3) - 4 sqrt(3) = sqrt(3).
