Look for a perfect cube factor of 16, which is 8. Writing cbrt(16) as cbrt(8 * 2) allows us to bring out the cube root of 8 (which is 2), yielding 2*cbrt(2).

To remove the cube root, cube both sides of the equation. The cube of 3 is 3 * 3 * 3, which equals 27. Therefore, x = 27.

There are 3600 seconds in one hour (60 minutes × 60 seconds). Therefore, one second is 1/3600 of an hour, which mathematically evaluates to approximately 0.000277... or rounded to 0.00027.

The boundaries correspond to roughly 0.333 and 0.875. Evaluating the options gives: 1/4 = 0.25, 23/24 ≈ 0.958, 11/12 ≈ 0.917, and 17/24 ≈ 0.708. Only 17/24 sits correctly within this boundary.

Multiply numerator and denominator by sqrt(3) to rationalize. This gives (3*sqrt(3)) / 3. The 3s cancel out, leaving just sqrt(3).

The bounds are 3/4 = 0.75 and 5/6 ≈ 0.833. Analyzing the options: 1/2 = 0.50, 2/3 ≈ 0.667, 4/5 = 0.80, and 9/10 = 0.90. The only fraction falling within the 0.75 to 0.833 range is 4/5.

Multiplying a square root by itself cancels out the radical, effectively squaring the square root. sqrt(6) * sqrt(6) is sqrt(36), which immediately simplifies to 6.

Subtracting the exponents 8 - 7 gives 1. Any variable raised to the power of 1 is just the variable itself, so a^1 is written simply as a.

Raising a number to the power of 1/3 is the same as finding its cube root. The cube root of 8 is 2, because 2^3 = 8.

Applying the exponent rule for division, subtract the exponent 4 from the exponent 6 while maintaining the base of 5. This results in 5^2.