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The MCQs below are drawn from the Applied Mathematics subject category.
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701
Determine the principal amount that generates Rs. 132 in interest at a rate of 10% per annum.
Using the simple interest formula SI = (P * R * T) / 100, we assume a time period of one year. Rearranging for P gives P = (SI * 100) / (R * T). Substituting the values: P = (132 * 100) / (10 * 1) = 1320.
702
Calculate the compound interest on a principal amount of Rs. 5,000 for a duration of 2 years at an annual interest rate of 4%.
To find the compound interest, use the formula A = P(1 + r/n)^(nt). Here, P = 5000, r = 0.04, and t = 2. The amount A = 5000 * (1.04)^2 = 5000 * 1.0816 = 5408. Subtracting the principal gives the interest: 5408 - 5000 = Rs. 408.
703
A town with a current population of 64,000 experiences an annual growth rate of 5%. What will be the population after 3 years?
To calculate the future population with compound growth, we use the formula P = P0 * (1 + r/100)^n. Here, P0 is 64,000, r is 5, and n is 3. Calculating 64,000 * (1.05)^3 results in 64,000 * 1.157625, which equals exactly 74,088. This represents the total population after three years of consistent growth.
704
Given a principal amount where the simple interest for 2 years at 7% per annum is Rs. 200, what is the difference between the compound interest and simple interest for the same period?
For a period of 2 years, the difference between compound interest and simple interest is calculated using the formula: Difference = P * (r/100)^2. Given SI = 200, r = 7, and t = 2, we find P = (200 * 100) / (7 * 2) = 1428.57. Applying the formula, the difference is 1428.57 * (0.07)^2, which equals approximately 7.
705
Calculate the annual interest rate if a principal of Rs. 1200 grows to Rs. 1440 over a period of 4 years.
The total interest earned is Rs. 1440 - Rs. 1200 = Rs. 240. Over 4 years, the annual interest is Rs. 240 / 4 = Rs. 60. The rate of interest is calculated as (Annual Interest / Principal) * 100, which is (60 / 1200) * 100 = 5%.
706
What principal amount will grow to Rs. 1600 in 5 years at a simple interest rate of 12% per annum?
Using the simple interest formula A = P(1 + rt/100), we have 1600 = P(1 + (12 * 5)/100). This simplifies to 1600 = P(1 + 0.60), or 1600 = 1.6P. Dividing 1600 by 1.6 gives a principal amount of 1000.
707
Calculate the principal amount that generates Rs. 60 as simple interest over 5 years at an annual interest rate of 6%.
Using the simple interest formula SI = (P * R * T) / 100, we rearrange to solve for P: P = (SI * 100) / (R * T). Substituting the values: P = (60 * 100) / (6 * 5) = 6000 / 30 = 200. The principal is Rs. 200.
708
Calculate the principal amount that generates a simple interest of Rs. 4320 at an annual interest rate of 4 percent over a period of 6 years.
The formula for simple interest is SI = (P * R * T) / 100. Rearranging to solve for the principal (P), we get P = (SI * 100) / (R * T). Substituting the given values: P = (4320 * 100) / (4 * 6) = 432000 / 24 = 18000. Therefore, the principal amount is Rs. 18,000.
709
Mohsin invests Rs. 15,000 at a compound interest rate of 5% per annum for 2 years. Calculate the total amount he will receive at the end of this period.
To calculate the compound interest amount, use the formula A = P(1 + r/n)^(nt). Here, P = 15000, r = 0.05, and t = 2. Calculating 15000 * (1.05)^2 results in 15000 * 1.1025, which equals Rs. 16,537.50. This confirms that the total amount accumulated after two years of compounding at a 5% annual rate is Rs. 16,537.50.
710
Calculate the time required for a principal amount of Rs. 1200 to generate an interest of Rs. 240 at a simple interest rate of 5% per annum.
Using the simple interest formula SI = (P * R * T) / 100, we substitute the given values: 240 = (1200 * 5 * T) / 100. This simplifies to 240 = 60 * T. Dividing both sides by 60, we find that T = 4 years. Therefore, the principal will earn the specified interest in exactly four years.